**Problem 1 :**

Find the quotient and remainder when

p(x) = 3x^{3} - 2x^{2} - 5 + 7x

is divided by d(x) = x + 3.

**Problem 2 :**

Find the quotient and remainder :

(x^{3} + x^{2} - 3 x + 5) ÷ (x - 1)

**Problem 3 :**

Find the quotient and remainder :

(3x^{3} - 2x^{2} + 7x - 5) ÷ (x + 3)

**Problem 4 :**

Find the quotient and remainder :

(3x^{3} + 4x^{2} - 10x + 6) ÷ (3x - 2)

**Problem 1 : **

Find the quotient and remainder when

p(x) = 3x^{3} - 2x^{2} - 5 + 7x

is divided by d(x) = x + 3.

**Solution :**

**Step 1 :**

Arrange dividend and the divisor in standard form.

Then,

3x^{3} - 2x^{2} + 7x - 5 (standard form of dividend)

x + 3 (standard form of divisor)

Write the coefficients of dividend in the first row.

Put ‘0’ for missing term(s).

3 -2 7 -5 (first row)

**Step 2 :**

Find out the zero of the divisor.

x + 3 = 0

x = -3

**Step 3 : **

Write the zero of divisor in front of dividend in the first row.

Put ‘0’ in the first column of second row.

**Step 4 : **

Complete the second row and third row as shown below.

All the entries except the last one in the third row are the coefficients of the quotient.

Therefore, the quotient is

3x^{2} - 11x + 40

and the remainder is

-125

**Problem 2 :**

Find the quotient and remainder :

(x^{3} + x^{2} - 3 x + 5) ÷ (x - 1)

**Solution :**

Arrange dividend and the divisor in standard form.

Then,

x^{3} + x^{2} - 3x + 5 (standard form of dividend)

x - 1 (standard form of divisor)

Find out the zero of the divisor.

x - 1 = 0

x = 1

Therefore, the quotient is

x^{2} + 2x - 1

and the remainder is

4

**Problem 3 :**

Find the quotient and remainder :

(3x^{3} - 2x^{2} + 7x - 5) ÷ (x + 3)

**Solution :**

Arrange dividend and the divisor in standard form.

Then,

3x^{3} - 2x^{2} + 7x - 5 (standard form of dividend)

x + 3 (standard form of divisor)

Find out the zero of the divisor.

x + 3 = 0

x = -3

Therefore, the quotient is

3x^{2} - 11x + 40

and the remainder is

-125

**Problem 4 :**

Find the quotient and remainder :

(3x^{3} + 4x^{2} - 10x + 6) ÷ (3x - 2)

**Solution :**

Arrange dividend and the divisor in standard form.

Then,

3x^{3} + 4x^{2} - 10x + 6 (standard form of dividend)

3x - 2 (standard form of divisor)

Find out the zero of the divisor.

3x - 2 = 0

x = 2/3

Therefore, the quotient is

3x^{2} + 6x - 6

and the remainder is

2

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