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#199–200

### Puzzles

Author: ExcelBI

All files (xlsx with puzzle and R with solution) for each and every puzzle are available on my Github. Enjoy.

### Puzzle #199

Data mining, maybe it is too big word for challenge we face today, but we need to dig up some information from given texts. Each of them have part number and order or delivery dates for each. Sometimes more than one. We need to extract them, clean if needed and sort by part and then by date. Little cleaning were needed so code is not as short as it could be. Check it.

```library(tidyverse)

path = "Power Query/PQ_Challenge_199.xlsx"
input = read_excel(path, range = "A1:A5")
test  = read_excel(path, range = "C1:D8")```

#### Transformation

```pattern_no = "\\d{3}"
pattern_date = "\\d{1,2}/+\\d{1,2}/+\\d{2}"

result = input %>%
mutate(`Part No.` = str_extract_all(String, pattern_no),
Date = str_extract_all(String, pattern_date)) %>%
unnest(Date, `Part No.`) %>%
mutate(Date = str_replace_all(Date, "//", "/")) %>%
select(-String) %>%
mutate(`Part No.` = as.numeric(`Part No.`),
Date = as.POSIXct(Date, format = "%m/%d/%y", tz = "UTC")) %>%
arrange(`Part No.`, Date)```

#### Validation

```identical(result, test)
# [1] TRUE```

### Puzzle #200

What we have here today. Exam reports of 6 students on 4 exams in 2 parts. Not a perfect situation, because we all like data in one place in nice structure, we like them tidy. So we have to tidy them up. Fortunatelly it is not so hard as it can look. Find out yourself.

```library(tidyverse)

path = "Power Query/PQ_Challenge_200.xlsx"
input1 = read_excel(path, range = "A1:D6")
input2 = read_excel(path, range = "F1:I6")
test = read_excel(path, range = "A11:E17")```

#### Transformation

```in1 = input1 %>%
pivot_longer(cols = -c(1), names_to = "subject", values_to = "score")
in2 = input2 %>%
pivot_longer(cols = -c(1), names_to = "subject", values_to = "score")

result = bind_rows(in1, in2) %>%
summarise(max = max(score), .by = c("subject", "Student")) %>%
pivot_wider(names_from = "subject", values_from = "max") %>%
arrange(Student)

result = result %>%
select(Student, sort(names(result)[2:5]))```

#### Validation

```identical(result, test)
# [1] TRUE```

Feel free to comment, share and contact me with advices, questions and your ideas how to improve anything. Contact me on Linkedin if you wish as well.

PowerQuery Puzzle solved with R was originally published in Numbers around us on Medium, where people are continuing the conversation by highlighting and responding to this story.