# How to create random binary matrices in R

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It all started off as a simple question from Scott Chamberlain on Twitter:

Make m x n matrix with randomly assigned 0/1 -> apply(m, c(1,2), function(x) sample(c(0,1),1)) — Better/faster solution? #rstats

— Scott Chamberlain (@recology_) August 28, 2012

The goal was to create a matrix with randomly selected binary elements, and a predetermined number of rows and columns, that looks something like this:

[,1] [,2] [,3] [,4] [1,] 0 1 1 0 [2,] 0 0 0 1 [3,] 1 0 1 1

Many suggestions followed (including one from me). There were several different ways suggested of creating the random binary values:

- Use the runif function to create random numbers between 0 and 1, and round to the nearest whole number.
- Use ifelse on the output of runif, and assign 0 if it's below 0.5, and 1 otherwise.
- Use the rbinom function to sample from a binomial distribution with a size of 1 and probability 0.5
- Use the sample function with the replace=TRUE option to simulate selections of 0 and 1.

There were also different ways suggested for generating the matrix:

- Use a for loop to fill each element of the matrix individually.
- Generate random numbers row by row, and fill the matrix using apply.
- Generate all the random numbers at once, and use the “matrix” function to create the matrix directly.

Luis Apiolaza reviews the suggested methods. Each has its merits: in clarity of code, in elegance, and especially in performance. On that front, Dirk Eddelbuettel benchmarked several of the solutions, including translating the code into C++ using Rcpp. One surprising outcome: translating the problem into C++ is only somewhat faster than using one call to sample. As Dirk says, this shows that “*well-written* R code can be competitive” with machine code.

Thinking inside the Box: Faster creation of binomial matrices

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