Monitoring Productivity II – the Others

September 30, 2011
By

(This article was first published on al3xandr3, and kindly contributed to R-bloggers)

In previous Monitoring Productivity Experiment post I looked into the hours I spent in computer, now will look into the hours Others spend in computer, which is far more interesting :) To find things like what day people spend more time on computer, how many hours they work, and general activity patterns.

Collecting data

In osx, is possible to use growl to display a message when a skype user signs in. So I configured growl to log the sign-in’s and sign-out’s of my skype contacts.

Like so:

> touch ~/Desktop/growl.log
> defaults write com.Growl.GrowlHelperApp GrowlLoggingEnabled -bool YES
> defaults write com.Growl.GrowlHelperApp GrowlLogType 1
> defaults write com.Growl.GrowlHelperApp "Custom log 1" ~/Desktop/growl.log

Instructions here.

And then I left my skype signed in for a few weeks, while I was on vacations. (not the best energy saving approach i know…)

Parsing data

Read the log file and create a semicolon separated file:

#!/usr/bin/env ruby
puts "timestamp;user;status"
File.open(ARGV[0]).each_line do |l|
  if l.include? "online" or l.include? "offline"
    date  = l.split('Skype')[0].strip
    user  = l.scan(/Skype:([^\(]*)/)[0][0].strip
    status = l.include?("online") ? "online" : "offline"
    puts "#{date};#{user};#{status}"
  end
end

Load it into R

data = read.csv("/my/proj/skype-growl/log.csv", sep=";", header=TRUE)

# parse dates "Aug 24, 2011 3:58:01 PM"
data$date = as.POSIXct(strptime(data$timestamp,"%b %d, %Y %I:%M:%S %p")) # DateTime
data$hour = format(data$date, format="%H:%M:%S")       # string
data$time = as.POSIXct(data$hour, format = "%H:%M:%S") # DateTime
data$day  = format(data$date, format="%m/%d/%y")       # string
data$weekday = format(data$date, format="%A")          # string

# filter for complete days of data
data = sqldf("select * from data where day >= '08/25/2011' and day <= '09/21/2011'")
sqldf("select count(distinct(day)) from data") 

27 days of data.

The sign-in’s and sign-out’s of a random person

randomperson = sqldf("select user from data group by random() limit 1")

d = sqldf(sprintf("select * 
                   from data 
                   where user = '%s' and day  >= '09/04/2011' and 
                   day  <= '09/12/2011'", randomperson[1,1]))

ggplot(data=d, aes(y=time, x=date)) + geom_point(aes(color=status), alpha=0.6) +  scale_x_datetime(major = "1 days") + scale_y_datetime(major = "1 hours")

Random Person

  • 10-Sep is Saturday and 11-Sep is Sunday, means skype was off on the weekend
  • start of workday between 9h-11h
  • end of workday between 18h-19h
  • skype is offline after working hours, except on night of Monday 05-Sep

Online Activity Patterns

Plotting all sign-in’s and sign-out’s over each weekday we can get a feeling for overall online activity:

ggplot(data, aes(x=time,..density..)) + geom_histogram() + facet_grid(weekday ~ .)

Daily Activity

  • Night time has less activity, and gets progressively smaller as night goes by
  • Around 9am activity spikes (people start work?)
  • Around 17h/18h activity spikes (people ending work?)
  • The 9h & 17h spikes are not so well formed in the weekend, thus very likelly connected to work
  • Sundays after dinner time(or so) people seems to start get online again before going to sleep
  • On weekends computer gets more use later in the day

How many hours people work?

More tricky to accurately measure but we can have a guess:

  • assuming that people are working during working hours of workdays
  • assuming that nobody start works before 6am, and nobody ends work after 21pm

Then, the first activity after 6am is start of work, and the last activity change before 21pm is the end of work.

d = sqldf("select user, 
                  day, 
                  weekday,
                  min(hour) as start, 
                  max(hour) as end
           from data
           where hour >= '06:00:00' and hour <= '21:00:00' and
                 weekday <> 'Saturday' and weekday <> 'Sunday'
           group by user, day")
d$totalhours = difftime(as.POSIXct(d$end, format = "%H:%M:%S"), as.POSIXct(d$start, format = "%H:%M:%S"))
d$totalhours = as.numeric(d$totalhours, units="hours")

# excude less than 2 hours/day, means bots, vacations, etc...
dt = sqldf("select * from d where totalhours > 2")

al3x.load() # my own collection of R functions
al3x.hist(dt, "totalhours")

Total Hours

Workday total hours are mostly between 6 and 12 hours, most common being the 8.5 hours/day.

Which day people spend more time in computer?

We can try counting the amount of sign-in’s/sign-out’s changes per day, means people are more likely to be in computer.

d = sqldf("select weekday, count(status) as amount
           from data
           group by weekday
           order by sum(time) DESC")
ggplot(d, aes(x=weekday,y=amount)) + geom_bar(stat="identity")

What day most active?

As the above could be biased in a number of ways lets use another way to measure it and if the results match then original estimate should be ok.

For example, way to go about it is to sum up the total working hours for each day:

d = sqldf("select user, 
                  day, 
                  weekday,
                  min(hour) as start, 
                  max(hour) as end
           from data
           where hour >= '06:00:00' and hour <= '21:00:00'
           group by user, day")
d$totalhours = difftime(as.POSIXct(d$end, format = "%H:%M:%S"), as.POSIXct(d$start, format = "%H:%M:%S"))
d$totalhours = as.numeric(d$totalhours, units="hours")

sqldf("select weekday, sum(totalhours) as amount
           from d
           group by weekday
           order by sum(totalhours) DESC")

Getting:

    weekday    amount
1   Tuesday 15404.471
2 Wednesday 15191.946
3    Monday 14298.472
4    Friday 12426.091
5  Thursday 11638.443
6  Saturday  5222.874
7    Sunday  5198.367

Almost same results, great.

Thus Tuesday is the day people spend more time in computer, and in decreasing order:

Tuesday > Wednesday > Monday > Friday > Thursday > (Saturday or Sunday)

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