**A**n easily phrased (and solved?) Le Monde mathematical puzzle that does not [really] require an R code:

*The five triplets A,B,C,D,E are such that*

*and*

*Given that*

*find the five triplets.*

**A**dding up both sets of equations shows everything solely depends upon E_{1}… So running an R code that checks for all possible values of E_{1} is a brute-force solution. However, one must first find what to check. Given that the sums of the triplets are of the form (16s,4s,s), the possible choices for E_{1} are necessarily restricted to

> S0=193+187+185+175
> ceiling(S0/16)
[1] 47
> floor((S0+175)/16)
[1] 57
> (47:57)*16-S0 #E1=S1-S0
[1] 12 28 44 60 76 92 108 124 140 156 172

**T**he first two values correspond to a second sum S_{2} equal to 188 and 192, respectively, which is incompatible with A_{1} being 193. Furthermore, the corresponding values for E_{2} and E_{3} are then given by

> S2==(49:57)*4
> E1=(49:57)*16-S0
> E2=S2-E1
> S3=S2/4
> S3-E2
[1] -103 -90 -77 -64 -51 -38 -25 -12 1

which excludes all values but E_{1}=172. No brute-force in the end…

Filed under: Books, Kids, R Tagged: Le Monde, mathematical puzzle, R, system of equations

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