# A Demo for the Ratio Estimation in Sampling Survey (Animation)

March 24, 2010
By

(This article was first published on Statistics, R, Graphics and Fun » R Language, and kindly contributed to R-bloggers)

Amber Watkins gave me a suggestion on the animation for the ratio estimation, and I think this is a good topic for my animation package. I’ve finished writing the initial version of the function sample.ratio() for this package, which will appear in the version 1.1-2 a couple of days later.

As we know, the benefit of ratio estimation is that sampling skewness may be adjusted for, because the estimation of $\reverse \bar{Y}$ will make use of the information in the relationship of X and Y: $\reverse \bar{X} \cdot (\bar{y}/\bar{x})$. Here is a demo (we can see the ratio estimate, denoted by the red line, generally performs better than $\reverse \bar{y}$):

An animation demo for the ratio estimation

And here is the code:

## To appear in animation 1.1-2: see documentation there
sample.ratio = function(x = runif(50, 0, 5), R = 1,
y = R * x + rnorm(x), size = length(x)/2, p.col = c("blue",
"red"), p.cex = c(1, 3), p.pch = c(20, 21), m.col = c("black",
"gray"), legend.loc = "topleft", ...) {
nmax = ani.options("nmax")
interval = ani.options("interval")
N = length(x)
for (i in 1:nmax) {
idx = sample(N, size)
plot(x, y, col = p.col[1], pch = p.pch[1], cex = p.cex[1],
...)

points(x[idx], y[idx], col = p.col[2], pch = p.pch[2],
cex = p.cex[2])
abline(v = c(mean(x), mean(x[idx])), h = c(mean(y), mean(y[idx])),
col = m.col, lty = c(2, 1))
abline(h = mean(x) * mean(y[idx])/mean(x[idx]), col = p.col[2])
legend(legend.loc, expression(bar(X), bar(x), bar(X) %.%
(bar(y)/bar(x)), bar(Y), bar(y)), lty = c(2, 1, 1,
2, 1), col = c(m.col[c(1, 2)], p.col[2], m.col[c(1,
2)]), bty = "n", ncol = 2)
Sys.sleep(interval)
}
}

library(animation)

sample.ratio()

## Save as an HTML page
ani.start()
sample.ratio(c(runif(50, 0, 2), runif(50, 4, 6)), size = 20)
ani.stop()

## Reproduce the above GIF animation
saveMovie({
set.seed(123)
sample.ratio(c(runif(50, 0, 2), runif(50, 4, 6)), size = 20)
}, moviename = "ratio-estimation", para = list(mar = c(4, 4,
1, 0.5), mgp = c(2, 1, 0)))


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