**A**nother quick riddle from the riddler: solve the equation

EXMREEK + EHKREKK = ?K?H?X?E

which involves every digit between 0 and 9. While the puzzle can be unravelled by considering first E and K, which must be equal to 6 and 3, a simple R code also leads to the conclusion

isok <- function(a,b){
s=as.numeric(unlist(strsplit(as.character(sum(10^(6:0)*a)+
sum(10^(6:0)*b)),"")))
if (length(s)==7){ goal=FALSE}else{
goal=(length(unique(c(a,b,s)))==10)&(a[2]==s[6])&
(s[8]==a[6])&(s[2]==a[7])&(b[2]==s[4])}
return(goal)}
pasok <- function(T=1e3){
for (t in 1:T){
a[1]=a[5]=a[6]=6;a[7]=3
digs=sample(c(0:2,4,5,7:9),4)
a[2:4]=digs[1:3] b[1]=a[1];b[2]=digs[4];
b[3]=a[7];b[4]=a[4];b[5]=a[1];b[6:7]=a[7]
if (isok(a=a,b=b))
print(rbind(a,b))}}
> pasok()
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
a 6 2 4 7 6 6 3
b 6 8 3 7 6 3 3

which sum is 13085296.

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