SR2 Chapter 3 Hard
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SR2 Chapter 3 Hard
Here’s my solutions to the hard exercises in chapter 3 of McElreath’s Statistical Rethinking, 2nd edition.
\(\DeclareMathOperator{\dbinomial}{Binomial} \DeclareMathOperator{\dbernoulli}{Bernoulli} \DeclareMathOperator{\dpoisson}{Poisson} \DeclareMathOperator{\dnormal}{Normal} \DeclareMathOperator{\dt}{t} \DeclareMathOperator{\dcauchy}{Cauchy} \DeclareMathOperator{\dexponential}{Exp} \DeclareMathOperator{\duniform}{Uniform} \DeclareMathOperator{\dgamma}{Gamma} \DeclareMathOperator{\dinvpamma}{Invpamma} \DeclareMathOperator{\invlogit}{InvLogit} \DeclareMathOperator{\logit}{Logit} \DeclareMathOperator{\ddirichlet}{Dirichlet} \DeclareMathOperator{\dbeta}{Beta}\)
Let’s first put the data into a tibble for easier manipulation later.
data(homeworkch3) df <- tibble(birth1 = birth1, birth2 = birth2) %>% mutate(birth = row_number())
birth1 | birth2 | birth |
---|---|---|
1 | 0 | 1 |
0 | 1 | 2 |
0 | 0 | 3 |
0 | 1 | 4 |
1 | 0 | 5 |
1 | 1 | 6 |
3H1
Let’s check we have the correct total cound and the correct number of boys.
h1_counts <- df %>% gather(order, gender, -birth) %>% summarise(boys = sum(gender), births = n())
Now we can grid approximate the posterior as before.
granularity <- 1000 h1_grid <- tibble(p = seq(0, 1, length.out = granularity)) %>% mutate(prior = 1) h1_posterior <- h1_grid %>% mutate( likelihood = dbinom(h1_counts$boys, h1_counts$births, p), posterior = prior * likelihood, posterior = posterior / sum(posterior) )
The maximum a posteriori (MAP) value is the value of p that maximises the posterior.
h1_map <- h1_posterior %>% slice(which.max(posterior)) %>% pull(p) h1_map [1] 0.5545546
3H2
We draw samples with weight equalt to the posterior. We then apply the HPDI
function to these samples, each time with a different width.
h2_samples <- h1_posterior %>% sample_n(10000, replace = TRUE, weight = posterior) %>% pull(p) h2_hpdi <- h2_samples %>% crossing(prob = c(0.5, 0.89, 0.97)) %>% group_by(prob) %>% group_map(HPDI) h2_hpdi [[1]] |0.5 0.5| 0.4574575 0.5735736 [[2]] |0.89 0.89| 0.4534535 0.6606607 [[3]] |0.97 0.97| 0.4294294 0.6616617
3H3
The posterior predictive samples are possible observations according to our posterior.
h3_posterior_predictive <- rbinom(10000, 200, h2_samples)
The number of observed births is very close to the MAP of the posterior predictive distribution, suggesting we have a decent fit.
3H4
Our data are from birth pairs and so far we didn’t make any distinction between the first and second births. To test this assumption, we can perform a posterior predictive check as in 3H3, but this time for first births.
h4_posterior_predictive <- rbinom(10000, 100, h2_samples)
The fit doesn’t look quite as good for first births as it did for all births together. It also doesn’t look bad since there is still a fair bit of probability mass around the observed number of first birth boys.
3H5
As the final posterior predictive check, let’s check the number of boys born after a girl.
h5_counts <- df %>% filter(birth1 == 0) %>% summarise(boys = sum(birth2), births = n()) h5_posterior_predictive <- rbinom(10000, h5_counts$births, h2_samples)
The fit here looks bad, since the observed number of boys is higher than the bulk of the model’s expectations.
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