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## Tips and tricks learned along the way

This is mostly a running list of data.table tricks that took me a while to figure out either by digging into the official documentation, adapting StackOverflow posts, or more often than not, experimenting for hours. I’d like to persist these discoveries somewhere with more memory than my head (hello internet) so I can reuse them after my mental memory forgets them. A less organized and concise addition to DataCamp’s sweet cheat sheet for the basics.

Most, if not all of these techniques were developed for real data science projects and provided some value to my data engineering. I’ve generalized everything to the mtcars dataset which might not make this value immediately clear in this slightly contrived context. This list is not intended to be comprehensive as DataCamp’s data.table cheatsheet is. OK, enough disclaimers!

Some more advanced functionality from data.table creator Matt Dowle here.

## => Columns of lists

##### summary table (long and narrow)

This could be useful, but is easily achievable using traditional methods.

dt <- data.table(mtcars)[, .(cyl, gear)]
dt[,unique(gear), by=cyl]
##    cyl V1
## 1:   6  4
## 2:   6  3
## 3:   6  5
## 4:   4  4
## 5:   4  3
## 6:   4  5
## 7:   8  3
## 8:   8  5
##### summary table (short and narrow)

Add all categories of gear for each cyl to original data.table as a list.

This is more nifty. It’s so simple, I find myself using this trick to quickly explore data ad hoc at the command line. Can also be useful for more serious data engineering.

dt <- data.table(mtcars)[,.(gear, cyl)]
dt[,gearsL:=list(list(unique(gear))), by=cyl]
##    gear cyl gearsL
## 1:    4   6  4,3,5
## 2:    4   6  4,3,5
## 3:    4   4  4,3,5
## 4:    3   6  4,3,5
## 5:    3   8    3,5
## 6:    3   6  4,3,5

### Accessing elements from a column of lists

Extract second element of each list in gearL1 and create row gearL1. This isn’t that groundbreaking, but explores how to access elements of columns which are constructed of lists of lists. lapply is your friend.

dt[,gearL1:=lapply(gearsL, function(x) x[2])]
dt[,gearS1:=sapply(gearsL, function(x) x[2])]

##    gear cyl gearsL gearL1 gearS1
## 1:    4   6  4,3,5      3      3
## 2:    4   6  4,3,5      3      3
## 3:    4   4  4,3,5      3      3
## 4:    3   6  4,3,5      3      3
## 5:    3   8    3,5      5      5
## 6:    3   6  4,3,5      3      3
## List of 6
##  $: num 3 ##$ : num 3
##  $: num 3 ##$ : num 3
##  $: num 5 ##$ : num 3
##  num [1:6] 3 3 3 3 5 3

Calculate all the gears for all cars of each cyl (excluding the current current row). This can be useful for comparing observations to the mean of groups, where the group mean is not biased by the observation of interest.

dt[,other_gear:=mapply(function(x, y) setdiff(x, y), x=gearsL, y=gear)]
##    gear cyl gearsL gearL1 gearS1 other_gear
## 1:    4   6  4,3,5      3      3        3,5
## 2:    4   6  4,3,5      3      3        3,5
## 3:    4   4  4,3,5      3      3        3,5
## 4:    3   6  4,3,5      3      3        4,5
## 5:    3   8    3,5      5      5          5
## 6:    3   6  4,3,5      3      3        4,5

## => Suppressing intermediate output with {}

This is actually a base R trick that I didn’t discover until working with data.table. See ?{ for some doucmentation and examples. I’ve only used it within the J slot of data.table, it might be more generalizable. I find it pretty useful for generating columns on the fly when I need to perform some multi-step vectorized operation. It can clean up code by allowing you to reference the same temporary variable by a concise name rather than rewriting the code to re-compute it.

dt <- data.table(mtcars)

Defaults to just returning the last object defined in the braces unnamed.

dt[,{tmp1=mean(mpg); tmp2=mean(abs(mpg-tmp1)); tmp3=round(tmp2, 2)}, by=cyl]
##    cyl   V1
## 1:   6 1.19
## 2:   4 3.83
## 3:   8 1.79

We can be more explicit by passing a named list of what we want to keep.

dt[,{tmp1=mean(mpg); tmp2=mean(abs(mpg-tmp1)); tmp3=round(tmp2, 2); list(tmp2=tmp2, tmp3=tmp3)}, by=cyl]
##    cyl     tmp2 tmp3
## 1:   6 1.191837 1.19
## 2:   4 3.833058 3.83
## 3:   8 1.785714 1.79

Can also write it like this without semicolons.

dt[,{tmp1=mean(mpg)
tmp2=mean(abs(mpg-tmp1))
tmp3=round(tmp2, 2)
list(tmp2=tmp2, tmp3=tmp3)},
by=cyl]
##    cyl     tmp2 tmp3
## 1:   6 1.191837 1.19
## 2:   4 3.833058 3.83
## 3:   8 1.785714 1.79

This is trickier with := assignments… I don’t think := is intended to work when wrapped in {. Assigning multiple columns with := at once does not allow you to use the first columns you create to use building the ones after it, as we did with = inside the { above. Chaining and then dropping unwanted variables is a messy workaround… still exploring this one.

dt <- data.table(mtcars)[,.(cyl, mpg)]

dt[,tmp1:=mean(mpg), by=cyl][,tmp2:=mean(abs(mpg-tmp1)), by=cyl][,tmp1:=NULL]
##    cyl  mpg     tmp2
## 1:   6 21.0 1.191837
## 2:   6 21.0 1.191837
## 3:   4 22.8 3.833058
## 4:   6 21.4 1.191837
## 5:   8 18.7 1.785714
## 6:   6 18.1 1.191837

## => Fast looping with set

I still haven’t worked much with the loop + set framework. I’ve been able to achieve pretty much everything with := which is more flexible and powerful. However, if you must loop, set is orders of magnitude faster than native R assignments within loops. Here’s a snippet from data.table news a while back:

New function set(DT,i,j,value) allows fast assignment to elements
of DT. Similar to := but avoids the overhead of [.data.table, so is
much faster inside a loop. Less flexible than :=, but as flexible
as matrix subassignment. Similar in spirit to setnames(), setcolorder(),
setkey() and setattr(); i.e., assigns by reference with no copy at all.

M = matrix(1,nrow=100000,ncol=100)
DF = as.data.frame(M)
DT = as.data.table(M)
system.time(for (i in 1:1000) DF[i,1L] <- i)   # 591.000s
system.time(for (i in 1:1000) DT[i,V1:=i])     #   1.158s
system.time(for (i in 1:1000) M[i,1L] <- i)    #   0.016s
system.time(for (i in 1:1000) set(DT,i,1L,i))  #   0.027s


data.table creators do favor set for some things, like this task which can also be done w/ lapply and .SD. I was actually directed to this solution after I posed this question on StackOverflow. I was also pleased to learn that the functionality I was looking for – applying a function to a subset of columns with .SDcols while preserving the untouched columns – was added as a feature request.

dt <- data.table(mtcars)[,1:5, with=F]
for (j in c(1L,2L,4L)) set(dt, j=j, value=-dt[[j]]) # integers using 'L' passed for efficiency
for (j in c(3L,5L)) set(dt, j=j, value=paste0(dt[[j]],'!!'))
##      mpg cyl  disp   hp   drat
## 1: -21.0  -6 160!! -110  3.9!!
## 2: -21.0  -6 160!! -110  3.9!!
## 3: -22.8  -4 108!!  -93 3.85!!
## 4: -21.4  -6 258!! -110 3.08!!
## 5: -18.7  -8 360!! -175 3.15!!
## 6: -18.1  -6 225!! -105 2.76!!

## => Using shift for to lead/lag vectors and lists

Note this feature is only available in version 1.9.5 (currently on Github, not CRAN) Base R surprisingly does not have great tools for dealing with leads/lags of vectors that most social science statistical software (Stata, SAS, even FAME which I used in my formative data years) come equipped with out of the box.

dt <- data.table(mtcars)[,.(mpg, cyl)]
dt[,mpg_lag1:=shift(mpg, 1)]
##     mpg cyl mpg_lag1 mpg_forward1
## 1: 21.0   6       NA         21.0
## 2: 21.0   6     21.0         22.8
## 3: 22.8   4     21.0         21.4
## 4: 21.4   6     22.8         18.7
## 5: 18.7   8     21.4         18.1
## 6: 18.1   6     18.7         14.3

#### shift with by

# creating some data
n <- 30
dt <- data.table(
date=rep(seq(as.Date('2010-01-01'), as.Date('2015-01-01'), by='year'), n/6),
ind=rpois(n, 5),
entity=sort(rep(letters[1:5], n/5))
)

setkey(dt, entity, date) # important for ordering
dt[,indpct_fast:=(ind/shift(ind, 1))-1, by=entity]

lagpad <- function(x, k) c(rep(NA, k), x)[1:length(x)]

##           date ind entity indpct_fast indpct_slow
##  1: 2010-01-01   6      a          NA          NA
##  2: 2011-01-01   5      a  -0.1666667  -0.1666667
##  3: 2012-01-01   4      a  -0.2000000  -0.2000000
##  4: 2013-01-01   3      a  -0.2500000  -0.2500000
##  5: 2014-01-01   3      a   0.0000000   0.0000000
##  6: 2015-01-01   3      a   0.0000000   0.0000000
##  7: 2010-01-01   6      b          NA          NA
##  8: 2011-01-01   3      b  -0.5000000  -0.5000000
##  9: 2012-01-01   4      b   0.3333333   0.3333333
## 10: 2013-01-01   1      b  -0.7500000  -0.7500000

## => Create multiple columns with := in one statement

This is useful, but note that that the columns operated on must be atomic vectors or lists. That is they must exist before running computation.
Building columns referencing other columns in this set need to be done indiviually or chained.

dt <- data.table(mtcars)[,.(mpg, cyl)]
dt[,:=(avg=mean(mpg), med=median(mpg), min=min(mpg)), by=cyl]
##     mpg cyl      avg  med  min
## 1: 21.0   6 19.74286 19.7 17.8
## 2: 21.0   6 19.74286 19.7 17.8
## 3: 22.8   4 26.66364 26.0 21.4
## 4: 21.4   6 19.74286 19.7 17.8
## 5: 18.7   8 15.10000 15.2 10.4
## 6: 18.1   6 19.74286 19.7 17.8

## => Assign a column with := named with a character object

This is the advised way to assign a new column whose name you already have determined and saved as a character. Simply surround the character object in parentheses.

dt <- data.table(mtcars)[, .(cyl, mpg)]

thing2 <- 'mpgx2'
dt[,(thing2):=mpg*2]

##    cyl  mpg mpgx2
## 1:   6 21.0  42.0
## 2:   6 21.0  42.0
## 3:   4 22.8  45.6
## 4:   6 21.4  42.8
## 5:   8 18.7  37.4
## 6:   6 18.1  36.2

This is old (now deprecated) way which still works for now. Not advised.

thing3 <- 'mpgx3'
dt[,thing3:=mpg*3, with=F]

##    cyl  mpg mpgx2 mpgx3
## 1:   6 21.0  42.0  63.0
## 2:   6 21.0  42.0  63.0
## 3:   4 22.8  45.6  68.4
## 4:   6 21.4  42.8  64.2
## 5:   8 18.7  37.4  56.1
## 6:   6 18.1  36.2  54.3

## => Calculate a function over a group (using by) excluding each entity in a second category.

This title probably doesn’t immediately make much sense. Let me explain what I’m going to calculate and why with an example. We want to compare the mpg of each car to the average mpg of cars in the same class (the same # of cylinders). However, we don’t want to bias the group mean by including the car we want to compare to the average in that average.

This assumption doesn’t appear useful in this example, but assume that gear+cyl uniquely identify the cars. In the real project where I faced this problem, I was calculating an indicator related to an appraiser relative to the average of all other appraisers in their zip3. (cyl was really zipcode and gear was the appraiser’s ID).

### METHOD 1: in-line

##### 0.a Biased mean: simple mean by cyl

However we want to know for each row, what is the mean among all the other cars with the same # of cyls, excluding that car.

dt <- data.table(mtcars)[,.(cyl, gear, mpg)]
dt[, mpg_biased_mean:=mean(mpg), by=cyl]
##    cyl gear  mpg mpg_biased_mean
## 1:   6    4 21.0        19.74286
## 2:   6    4 21.0        19.74286
## 3:   4    4 22.8        26.66364
## 4:   6    3 21.4        19.74286
## 5:   8    3 18.7        15.10000
## 6:   6    3 18.1        19.74286
dt[, dt[!gear %in% unique(dt$gear)[.GRP], mean(mpg), by=cyl], by=gear] #unbiased mean ## gear cyl V1 ## 1: 4 6 19.73333 ## 2: 4 8 15.10000 ## 3: 4 4 25.96667 ## 4: 3 6 19.74000 ## 5: 3 4 27.18000 ## 6: 3 8 15.40000 ## 7: 5 6 19.75000 ## 8: 5 4 26.32222 ## 9: 5 8 15.05000 # check dt[gear!=4 & cyl==6, mean(mpg)] ## [1] 19.73333 ##### 1.b Same as 1.a, but a little faster uid <- unique(dt$gear)
dt[, dt[!gear %in% (uid[.GRP]), mean(mpg), by=cyl] , by=gear][order(cyl, gear)] #unbiased mean
##    gear cyl       V1
## 1:    3   4 27.18000
## 2:    4   4 25.96667
## 3:    5   4 26.32222
## 4:    3   6 19.74000
## 5:    4   6 19.73333
## 6:    5   6 19.75000
## 7:    3   8 15.40000
## 8:    4   8 15.10000
## 9:    5   8 15.05000
##### Why does this work?
# 1.a pulling it apart with .GRP
dt[, .GRP, by=cyl]
##    cyl .GRP
## 1:   6    1
## 2:   4    2
## 3:   8    3
dt[, .(.GRP, unique(dt$gear)[.GRP]), by=cyl] ## cyl .GRP V2 ## 1: 6 1 4 ## 2: 4 2 3 ## 3: 8 3 5 dt[,dt[, .(.GRP, unique(dt$gear)[.GRP]), by=cyl], by=gear]
##    gear cyl .GRP V2
## 1:    4   6    1  4
## 2:    4   4    2  3
## 3:    4   8    3  5
## 4:    3   6    1  4
## 5:    3   4    2  3
## 6:    3   8    3  5
## 7:    5   6    1  4
## 8:    5   4    2  3
## 9:    5   8    3  5
##### 1.b Setting key
setkey(dt, gear)
##### Method 3:
system.time(dt[,unbiased_mean_vectorized:=leaveOneOutMean(.SD, ind='mpg', bybig='cyl', bysmall='gear')])
##    user  system elapsed
##   0.034   0.003   0.038
system.time(tmp <- dt[,dt[!gear %in% unique(dt$gear)[.GRP], mean(mpg), by=cyl], by=gear] ) ## user system elapsed ## 3.934 0.377 4.311 ##### Method 1: uid <- unique(dt$gear)
system.time(dt[, dt[!gear %in% (uid[.GRP]), mean(mpg), by=cyl] , by=gear][order(cyl, gear)])
##    user  system elapsed
##   3.527   0.346   3.874

## => keyby to key resulting aggregate table

##### Without keyby

Categories are not sorted

## devtools::install_github('brooksandrew/Rsenal')
library('Rsenal') # grabbing depthbin function
tmp <- dt[, .(N=.N, sum=sum(vs), mean=mean(vs)/.N), by=depthbin(mpg, 5, labelOrder=T)]
tmp
##           depthbin     N   sum         mean
## 1: [10.4,15.2] 1/5 24978     0 0.000000e+00
## 2: (24.4,33.9] 5/5 18740 15591 4.439508e-05
## 3:   (17.8,21] 3/5 21934  6221 1.293077e-05
## 4: (15.2,17.8] 2/5 15585  3089 1.271757e-05
## 5:   (21,24.4] 4/5 18763 18763 5.329638e-05
tmp[,barplot(mean, names=depthbin, las=2)]

##      [,1]
## [1,]  0.7
## [2,]  1.9
## [3,]  3.1
## [4,]  4.3
## [5,]  5.5
##### With keyby
## devtools::install_github('brooksandrew/Rsenal')
library('Rsenal')
tmp <- dt[, .(N=.N, sum=sum(vs), mean=mean(vs)/.N), keyby=depthbin(mpg, 5, labelOrder=T)]
tmp
##           depthbin     N   sum         mean
## 1: [10.4,15.2] 1/5 24978     0 0.000000e+00
## 2: (15.2,17.8] 2/5 15585  3089 1.271757e-05
## 3:   (17.8,21] 3/5 21934  6221 1.293077e-05
## 4:   (21,24.4] 4/5 18763 18763 5.329638e-05
## 5: (24.4,33.9] 5/5 18740 15591 4.439508e-05
tmp[,barplot(mean, names=depthbin, las=2)]

##      [,1]
## [1,]  0.7
## [2,]  1.9
## [3,]  3.1
## [4,]  4.3
## [5,]  5.5

## => Using [1], [.N], setkey and by for within group subsetting

#### take highest value of column A when column B is highest by group

Max of qsec for each category of cyl (this is easy)

dt <- data.table(mtcars)[, .(cyl, mpg, qsec)]
dt[, max(qsec), by=cyl]
##    cyl    V1
## 1:   6 20.22
## 2:   4 22.90
## 3:   8 18.00
##### value of qsec when mpg is the highest per category of cyl

(this is trickier)

setkey(dt, mpg)
dt[,qsec[.N],  by=cyl]
##    cyl    V1
## 1:   8 17.05
## 2:   6 19.44
## 3:   4 19.90
##### value of qsec when mpg is the lowest per category of cyl
dt[,qsec[1],  by=cyl]
##    cyl    V1
## 1:   8 17.98
## 2:   6 18.90
## 3:   4 18.60
##### value of qsec when mpg is the median per category of cyl
dt[,qsec[round(.N/2)],  by=cyl]
##    cyl   V1
## 1:   8 18.0
## 2:   6 15.5
## 3:   4 16.7
##### subset rows within by statement

V1 is the standard deviation of mpg by cyl. V2 is the standard deviation of mpg for just the first half of mpg.

dt <- data.table(mtcars)
setkey(dt,mpg)
dt[, .(sd(mpg), sd(mpg[1:round(.N/2)])), by=cyl]
##    cyl       V1        V2
## 1:   8 2.560048 2.0926174
## 2:   6 1.453567 0.8981462
## 3:   4 4.509828 1.7728508

## => Passing data.table column names as function arguments

#### Method 1: No quotes, and deparse + substitute

This way seems more data.table-ish because it maintains the practice of not using quotes on variable names in most cases.

dt <- data.table(mtcars)[,.(cyl, mpg)]
myfunc <- function(dt, v) {
v2=deparse(substitute(v))
dt[,v2, with=F][[1]] # [[1]] returns a vector instead of a data.table
}

myfunc(dt, mpg)
##  [1] 21.0 21.0 22.8 21.4 18.7 18.1 14.3 24.4 22.8 19.2 17.8 16.4 17.3 15.2
## [15] 10.4 10.4 14.7 32.4 30.4 33.9 21.5 15.5 15.2 13.3 19.2 27.3 26.0 30.4
## [29] 15.8 19.7 15.0 21.4

### Method 2: quotes and get

However I tend to pass through column names as characters (quoted) and use get each time I reference that column. That can be annoying if you have a long function repeatedly reference column names, but I often need to write such few lines of code with data.table, it hasn’t struck me as terribly unslick, yet.

dt <- data.table(mtcars)
myfunc <- function(dt, v) dt[,get(v)]

myfunc(dt, 'mpg')
##  [1] 21.0 21.0 22.8 21.4 18.7 18.1 14.3 24.4 22.8 19.2 17.8 16.4 17.3 15.2
## [15] 10.4 10.4 14.7 32.4 30.4 33.9 21.5 15.5 15.2 13.3 19.2 27.3 26.0 30.4
## [29] 15.8 19.7 15.0 21.4

## => Beware of scoping within data.table

### data.frame way

When you add something to a data.frame within a function that exists in the global environment, it does not affect that object in the global environment unless you return and reassign it as such, or you use the <<- operator.

df <- mtcars[,c('cyl', 'mpg')]
df$addcol1<- 'here in func!' df$addcol2 <<- 'in glob env!'
return(df)
}

When we call the function, we see addcol1 in the output. But not addcol2. That’s because it’s been added to the df in the global environment one level up.

head(add_column_df(df))
## Mazda RX4           6 21.0 here in func!
## Mazda RX4 Wag       6 21.0 here in func!
## Datsun 710          4 22.8 here in func!
## Hornet 4 Drive      6 21.4 here in func!
## Hornet Sportabout   8 18.7 here in func!
## Valiant             6 18.1 here in func!

Here is addcol2, but not addcol.

head(df)
## Mazda RX4           6 21.0 in glob env!
## Mazda RX4 Wag       6 21.0 in glob env!
## Datsun 710          4 22.8 in glob env!
## Hornet 4 Drive      6 21.4 in glob env!
## Hornet Sportabout   8 18.7 in glob env!
## Valiant             6 18.1 in glob env!

### data.table way

Unlike data.frame, the := operator adds a column to both the object living in the global environment and used in the function. I think this is because these objects are tactually the same object. data.table shaves computation time by not making copies unless explicity directed to.

dt <- data.table(mtcars)
dat[,addcol:='sticking_to_dt!'] # hits dt in glob env
return(dat)
}
##     mpg cyl disp  hp drat    wt  qsec vs am gear carb          addcol
## 1: 21.0   6  160 110 3.90 2.620 16.46  0  1    4    4 sticking_to_dt!
## 2: 21.0   6  160 110 3.90 2.875 17.02  0  1    4    4 sticking_to_dt!
## 3: 22.8   4  108  93 3.85 2.320 18.61  1  1    4    1 sticking_to_dt!
## 4: 21.4   6  258 110 3.08 3.215 19.44  1  0    3    1 sticking_to_dt!
## 5: 18.7   8  360 175 3.15 3.440 17.02  0  0    3    2 sticking_to_dt!
## 6: 18.1   6  225 105 2.76 3.460 20.22  1  0    3    1 sticking_to_dt!
##     mpg cyl disp  hp drat    wt  qsec vs am gear carb          addcol
## 1: 21.0   6  160 110 3.90 2.620 16.46  0  1    4    4 sticking_to_dt!
## 2: 21.0   6  160 110 3.90 2.875 17.02  0  1    4    4 sticking_to_dt!
## 3: 22.8   4  108  93 3.85 2.320 18.61  1  1    4    1 sticking_to_dt!
## 4: 21.4   6  258 110 3.08 3.215 19.44  1  0    3    1 sticking_to_dt!
## 5: 18.7   8  360 175 3.15 3.440 17.02  0  0    3    2 sticking_to_dt!
## 6: 18.1   6  225 105 2.76 3.460 20.22  1  0    3    1 sticking_to_dt!

So something like this renaming the local version using copy bypasses this behavior, but is likely somewhat less efficient (and elegant). I suspect there’s a cleaner and/or faster way to do this: keep some variables local to the function while persisting and returning other columns.

dt <- data.table(mtcars)
datloc <- copy(dat)
datloc[,addcol:='not sticking_to_dt!'] # hits dt in glob env
return(datloc)
}
##     mpg cyl disp  hp drat    wt  qsec vs am gear carb              addcol
## 1: 21.0   6  160 110 3.90 2.620 16.46  0  1    4    4 not sticking_to_dt!
## 2: 21.0   6  160 110 3.90 2.875 17.02  0  1    4    4 not sticking_to_dt!
## 3: 22.8   4  108  93 3.85 2.320 18.61  1  1    4    1 not sticking_to_dt!
## 4: 21.4   6  258 110 3.08 3.215 19.44  1  0    3    1 not sticking_to_dt!
## 5: 18.7   8  360 175 3.15 3.440 17.02  0  0    3    2 not sticking_to_dt!
## 6: 18.1   6  225 105 2.76 3.460 20.22  1  0    3    1 not sticking_to_dt!
##     mpg cyl disp  hp drat    wt  qsec vs am gear carb
## 1: 21.0   6  160 110 3.90 2.620 16.46  0  1    4    4
## 2: 21.0   6  160 110 3.90 2.875 17.02  0  1    4    4
## 3: 22.8   4  108  93 3.85 2.320 18.61  1  1    4    1
## 4: 21.4   6  258 110 3.08 3.215 19.44  1  0    3    1
## 5: 18.7   8  360 175 3.15 3.440 17.02  0  0    3    2
## 6: 18.1   6  225 105 2.76 3.460 20.22  1  0    3    1

## 4. PRINTING

Nothing groundbreaking here, but a small miscellaneous piece of functionality. In data.frame world, wrapping an expression in () prints the output to the console. This also works with data.table, but there is another way. In data.table this is achieved by appending [] to the end of the expression. I find this useful because when I’m exploring at the console, I don’t usually decide to print the output until I’m almost done and I’m already at the end of the expression I’ve written.

# data.frame way of printing after an assignment
df <- head(mtcars) # doesn't print
(df <- head(mtcars)) # does print
##                    mpg cyl disp  hp drat    wt  qsec vs am gear carb
## Mazda RX4         21.0   6  160 110 3.90 2.620 16.46  0  1    4    4
## Mazda RX4 Wag     21.0   6  160 110 3.90 2.875 17.02  0  1    4    4
## Datsun 710        22.8   4  108  93 3.85 2.320 18.61  1  1    4    1
## Hornet 4 Drive    21.4   6  258 110 3.08 3.215 19.44  1  0    3    1
## Hornet Sportabout 18.7   8  360 175 3.15 3.440 17.02  0  0    3    2
## Valiant           18.1   6  225 105 2.76 3.460 20.22  1  0    3    1
# data.table way of printing after an assignment
dt <- data.table(head(mtcars)) # doesn't print
dt[,hp2wt:=hp/wt][] # does print
##     mpg cyl disp  hp drat    wt  qsec vs am gear carb    hp2wt
## 1: 21.0   6  160 110 3.90 2.620 16.46  0  1    4    4 41.98473
## 2: 21.0   6  160 110 3.90 2.875 17.02  0  1    4    4 38.26087
## 3: 22.8   4  108  93 3.85 2.320 18.61  1  1    4    1 40.08621
## 4: 21.4   6  258 110 3.08 3.215 19.44  1  0    3    1 34.21462
## 5: 18.7   8  360 175 3.15 3.440 17.02  0  0    3    2 50.87209
## 6: 18.1   6  225 105 2.76 3.460 20.22  1  0    3    1 30.34682

## => Hide output from := with knitr

It used to be that assignments using the := operator printed the object to console when knitting documents with knitr and rmarkdown. This is actually fixed in data.table v1.9.5. However at the time of my writing, this currently not available on CRAN… only Github. For 1.9.4 users, this StackOverflow post has some hacky solutions. This least impedance approach I found was simply wrapping the expression in invisible. Other solutions alter the way you use data.table which I didn’t like.

dt <- data.table(mtcars)
dt[,mpg2qsec:=mpg/qsec] # will print with knitr
invisible(dt[,mpg2qsec:=mpg/qsec]) # won't print with knitr