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**A 3.0 MeV proton is incident on a potential energy barrier of thickness 10fm and height 10 MeV. What is the transmission coefficient T.**

And here is what I have tried:

[tex]T=e^(-2bL)[/tex]

[tex]b=\sqrt{\frac{8\pi^2m(U_b-E)}{h^2}}[/tex]

[tex]b=\sqrt{\frac{8\pi^2(1.673*10^-27)\frac{10*10^6 - 3*10^6}{1.602*10^-19}}{(6.626*10^-34)^2}}[/tex]

[tex]b=3.626*10^33[/tex]

This gives me a transmission coeffecient of approximately 0, and the answer given in the book is 9.02*10^-6. Your help on this is much appreciated.