"Inside" Functors — Evaluating things more than once
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(The examples here work with the version of insidefunctor tagged as “v1”)
I ran into an interesting problem using “inside” functors.
Something is wrong in the following code (well, depending on what you thought it should do).
> library(insidefunctor)
> `%+.%` = fmap(`+`)
> x = seq(0, 10, len = 50)
> plot(x, collect(each(x) %+.% runif(1)))
It’s clear that in constructions like each(x) + y
, y is only
going to be evaluated once. Of course, the preceding example could have been
written
> plot(x, collect(each(x) %+.% each(runif(length(x)))))
but I think that that is not as grammatically pretty.
But, since we solved the last grammatical problem with a hacky use of
insidefunctors, why not try the same trick? Say we define an inside functor
meval
(for multipleevaluations) that behaves like this:
meval(expr)
returns a promise to evaluateexpr
func(meval(expr))
returns a promise to evaluatefunc(expr)
collect(meval(expr))
evaluates it finally.
That is, the unevaluated chain keeps growing until it is finally collected, at which point a value results.
So let’s define that.
> meval = function(expr, level=1) {
> expr = substitute(expr)
> callback = function () {
> eval(expr)
> }
> make.meval(callback, level=level, depth=1)
> }
> make.meval = function(callback, level, depth) {
> functor = inside.functor(level, depth)
> functor$callback = callback
>
> class(functor) = c(‘meval’, class(functor))
>
> functor
> }
> apply.functor.meval = function(
> inside,
> func,
> args,
> caller
> )
> {
> our.level = level(inside)
>
> args.boxed = args
> for (i in seq_along(args.boxed)) {
> arg = args.boxed[[i]]
>
> if (is.inside.functor(arg) && level(arg)>=our.level) {
> }
> else {
> args.boxed[[i]] = list(
> callback = function() {
> arg
> }
> )
> }
> }
> max.depth = max(sapply(args.boxed, depth))
>
> callback = function() {
> piece.args = lapply(args.boxed, function (arg) {
> arg$callback()
> })
> caller(func, piece.args)
> }
>
> make.meval(
> callback,
> level = our.level,
> depth = max.depth
> )
> }
> collect.end.meval = function(inside) {
> inside$callback()
> }
And test it.
> promise = meval(runif(1))
> collect(promise)
0.633877807762474
> collect(promise)
0.236430999357253
Works so far. Now try the motivating example:
> plot(x, collect.all(each(x, l = 2) %+.% meval(runif(1))))
Oh god no it’s this problem again.
arg
isn’t being remembered in
> args.boxed[[i]] = list(
> callback = function() {
> arg
> }
> )
so the fix is to
> apply.functor.meval = function(
> inside,
> func,
> args,
> caller
> )
> {
> our.level = level(inside)
>
> args.boxed = args
> for (i in seq_along(args.boxed)) {
> arg = args.boxed[[i]]
>
> if (is.inside.functor(arg) && level(arg)>=our.level) {
> }
> else {
> args.boxed[[i]] = (function(arg) {
> force(arg)
> list(
> callback = function() {
> arg
> }
> )
> })(arg)
> }
> }
> max.depth = max(sapply(args.boxed, depth))
>
> callback = function() {
> piece.args = lapply(args.boxed, function (arg) {
> arg$callback()
> })
> caller(func, piece.args)
> }
>
> make.meval(
> callback,
> level = our.level,
> depth = max.depth
> )
> }
Which is ugly but works. Then:
> plot(x, collect.all(each(x, l = 2) %+.% meval(runif(1))))
Now the real challenge is to understand why the above code works, but interchanging the levels (ie making the each() happen before the meval()) does not:
> plot(x, collect.all(each(x) %+.% meval(runif(1), l = 2)))
And, given that you obviously wanted it to go the first way or why would you have used meval(), is there any way to modify the semantics so that only the first way makes sense (and is that a good idea?), which brings us to…
About those level
s…
They’re yucky. Also note that the call to collect.all
in the preceding example is really doing 2 collects, even though
the functors are only ever written 1 deep.
The reason is that expressions like
> x = c(1, 2, 3)
> y = c(4, 5)
> collect.all(each(x, l = 2) %+.% each(y))

5 6

6 7

7 8
behave like (inserting for the xs)
> collect.all(
> each(x)
> %+.%
> each(
> lapply(x, function(x.) each(y))
> )
> )

5 6

6 7

7 8
which behaves like (inserting for the ys)
> collect.all(
> each(
> lapply(x, function(x.)
> each(
> lapply(y, function(y) x.)
> )
> )
> )
> %+.%
> each(
> lapply(x, function(x) each(y))
> )
> )

5 6

6 7

7 8
ie only when the levels are the same do the eaches “line up” and remain a single each. When the levels are different they “miss” each other and become two nested eaches. This is by design but it still feels messy.
Suppose we were to bring back the suggestion of the name “corresponding” that we mentioned earlier:
> each(x) %+.% corresponding(y)
would stand for when the levels are identical; in any other case the levels would be assumed to be different and the functors would “overlap”.
The advantage to this notation is that only when the word “each” is actually used is another level introduced. Plus it aligns more closely with English.
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