Example 8.36: Quadratic equation with real roots

[This article was first published on SAS and R, and kindly contributed to R-bloggers]. (You can report issue about the content on this page here)
Want to share your content on R-bloggers? click here if you have a blog, or here if you don't.

We often simulate data in SAS or R to confirm analytical results. For example, consider the following problem from the excellent text by Rice:

Let U1, U2, and U3 be independent random variables uniform on [0, 1]. What is the probability that the roots of the quadratic U1*x^2 + U2*x + U3 are real?

Recall that for a quadratic equation A*x^2 + B*x + C to have real roots we need the discriminant (B^2-4AC) to be non-negative.

The answer given in the second and third editions of Rice is 1/9. Here’s how you might get there:

Since, B^2 > 4*A*C <=> B > 2*sqrt(A*C), we need to integrate B over the range 2*sqrt(a*c) to 1, then integrate over all possible values for A and C (each from 0 to 1).

Another answer can be found by taking y = b^2 and w = 4ac and integrating over their joint distribution (they’re independent, of course). That leads to an answer of approximately 0.254. Here’s how to calculate this in R:

f = function(x) {
  A = x[1]; B = x[2]; C = x[3];
  return(as.numeric(B^2 > 4*A*C))
adaptIntegrate(f, c(0,0,0), c(1,1,1), tol=0.0001, max=1000000)

which generates the following output:

[1] 0.2543692

[1] 0.005612558

[1] 999999

[1] -1

We leave the details of the calculations aside for now, but both seem equally plausible, at first glance. A quick simulation can suggest which is correct.

For those who want more details, here’s a more complete summary of this problem and solution.


Neither the SAS nor the R code is especially challenging.

data test;
  do trial = 1 to 10000;
    u1 = uniform(0); u2 = uniform(0); u3 = uniform(0);
    res = u2**2 - 4*u1*u3;
    realroot = (res ge 0);

proc print data=test (obs=10); 

proc means data=test;
  var realroot;

Leading to the result:

                        The MEANS Procedure

                   Analysis Variable : realroot

     N           Mean        Std Dev        Minimum        Maximum
 10000      0.2556000      0.4362197              0      1.0000000


numsim = 10000
u1 = runif(numsim); u2 = runif(numsim); u3 = runif(numsim)
res = u2^2 - 4*u1*u3
realroots = res>=0

With the result

0.747 0.253 

The simulation demonstrates both that the first solution is incorrect. Here the simulation serves as a valuable check for complicated analysis.

Insights into where the 1/9 solution fails would be welcomed in the comments.

To leave a comment for the author, please follow the link and comment on their blog: SAS and R.

R-bloggers.com offers daily e-mail updates about R news and tutorials about learning R and many other topics. Click here if you're looking to post or find an R/data-science job.
Want to share your content on R-bloggers? click here if you have a blog, or here if you don't.

Never miss an update!
Subscribe to R-bloggers to receive
e-mails with the latest R posts.
(You will not see this message again.)

Click here to close (This popup will not appear again)