# minimax, maximin or plain

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**A** simple riddle from The Riddler on choosing between the maximum between two minima of two throws of an N-face dice, the minimum between two maxima of two throws of an N-face dice, and a single throw. Since maximin is always less than maximin, second choice is always worse than first and a stochastic domination version of the argument shows the single throw should stand in the middle.

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