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## Homework Statement

(a) Show that in the Bohr model, the frequency of revo-lution of an electron in its circular orbit around a stationary hydrogen nucleus is f = me

^{4}/4ε

_{0}

^{2}n

^{3}h

^{3}(b) In classical physics, the frequency of revolution of the electron is equal to the frequency of the radiation that it emits. Show that when n is very large, the fre-quency of revolution does indeed equal the radiated frequency cal-culated from Eq. (39.5) for a transition from n

_{1}= n + 1 to n

_{2}= n.

## Homework Equations

v = e

^{2}/2ε

_{0}nh

r = ε

_{0}n

^{2}h

^{2}/πme

^{2}

## The Attempt at a Solution

I managed to solve part (a). But for part (b), I'm not sure how to find the energy of the photon. I tried

E = -13.6eV (1/n

^{2}- 1/(n+1)

^{2}) which I expanded to get

E = -13.6eV ((2n+1)/n

^{2}(n+1)

^{2}) but doesn't this tend to 0 as n approaches infinity? Since E = hf this implies that f tends to 0 as well? Does anybody know how to prove the relationship in part (b)? Thanks! :)