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Scenario: we got a table of id-value, and a matrix/tibble that contains the id, and we need the labels.

It may be useful when predicting the Key (or Ids) of in a classification model (like in Keras), and we need the labels as the final output.

There are two interesting things:

- The usage of apply based on column and rows at the same time.
- The creation of an empty tibble and how to fill it (append columns)

```
library(tibble)
# mapping table (id-value)
map_table=tibble(id=c(1,2,3),
value=c("a", "b", "c")
)
map_table
```

```
## # A tibble: 3 x 2
## id value
##
```
## 1 1 a
## 2 2 b
## 3 3 c

```
# given a key, retrun the label
get_label <- function(x)
{
id_flag=map_table$id==x
res=as.character(map_table[id_flag, 2])
return(res)
}
# the data to get the label
X_data=tibble(v1=c(1,2,3),
v2=c(2,2,2),
v3=c(3,2,1)
)
X_data
```

```
## # A tibble: 3 x 3
## v1 v2 v3
##
```
## 1 1 2 3
## 2 2 2 2
## 3 3 2 1

## Option 1: as matrix

```
mat_res=apply(X_data, 1:2, get_label)
## Checking...
mat_res
```

```
## v1 v2 v3
## [1,] "a" "b" "c"
## [2,] "b" "b" "b"
## [3,] "c" "b" "a"
```

## Option 2: as tibble

```
# creating a 1 column with NAs same length as nrow(X_data)
tib_res=tibble(V1=rep(NA, nrow(X_data)))
for(i in 1:ncol(X_data))
{
vec=X_data[,i]
vec_lbl=sapply(t(vec), get_label) # if X_data is a matrid, no need to transpose with t()
tib_res[,i]=vec_lbl
}
## Checking...
tib_res
```

```
## # A tibble: 3 x 3
## V1 V2 V3
##
```
## 1 a b c
## 2 b b b
## 3 c b a

Option 2, to my surprise, is faster.

I didnâ€™t use the `add_column`

because of the need of replacing the first dummy `NA`

column.

Other approaches may include dictionaries.

Any improvement in the code is welcome.

Thanks for reading ðŸš€

Blog | Linkedin | Twitter | ðŸ“— Data Science Live Book

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