Euler Problem 13: Large Sum of 1000 Digits

February 22, 2017
By

(This article was first published on The Devil is in the Data, and kindly contributed to R-bloggers)

Euler Problem 13 asks to add one hundred numbers with fifty digits. This seems like a simple problem where it not that most computers are not designed to deal with numbers with a lot of integers. For example:

 2^{64} = 18446744073709551616

When asking R to compute this value we get 1.844674e+19, losing most of the digits and limiting the accuracy of the results. Computers solve this problem using Arbitrary-precision Arithmetic. There are many software libraries that can process long integers without loosing accuracy. Euler Problem 13 requires this type of approach.

Euler Problem 13 Definition

Work out the first ten digits of the sum of the following one-hundred 50-digit numbers.

Solution

The easy way to solve this problem is to use the gmp package for working with very large integers. This package uses a special number types such as Big Rational and Big Integer. The number of digits in these number types is only limited by the size of the memory.

library(gmp)
numbers <- readLines("Euler/p013_numbers.txt")
digits <- as.bigz(sum(as.numeric(numbers)))
answer <- substr(as.character(digits),1,10)

To find the solution to this problem using only base R, I wrote a function to add numbers using strings instead of integers. The function adds leading zeros to the smallest number to make them both the same length. The function then proceeds to add numbers in the same way we were taught in primary school. This function can in principle be used for several other Euler Problems using large integers.

# Add numbers with many digits
big.add <- function(a, b) {
    # Add leading zeros to smallest numer
    if (nchar(a) < nchar(b)) 
        a <- paste0(paste(rep(0, nchar(b)-nchar(a)), collapse=""), a) 
    if (nchar(a) > nchar(b)) 
        b <- paste0(paste(rep(0, nchar(a)-nchar(b)), collapse=""), b)
    solution <- vector()
    remainder <- 0
    for (i in nchar(b):1) {
        p <- as.numeric(substr(a, i, i))
        q <- as.numeric(substr(b, i, i))
        r <- p + q + remainder if (r >= 10 & i!=1) {
            solution <- c(solution, r %% 10)
            remainder <- (r - (r %% 10))/10
        } else {
            solution <- c(solution, r)
            remainder <- 0
        }
    }
    return(paste(rev(solution), collapse=""))
}

With this function, the problem is easy to solve. The second part of the code runs this function over the one hundred numbers provided on the Euler Problem page and calculates the answer.

numbers <- readLines("Euler/p013_numbers.txt")
answer <- "0"
for (i in numbers) {
    answer <- big.add(answer, i)
}
answer <- substr(answer, 1, 10)

Multiplying Big Numbers

You can expand this function to multiply a very large number with a smaller number using the Reduce function. This function adds the number a to itself, using the big.add function. The outcome of the addition is used in the next iteration until it has been repeated b times. The number b in this function needs to be a ‘low’ number because it uses a vector of the length b.

big.mult <- function(a, b) {
    Reduce(big.add, rep(a, as.numeric(b)))
}

The post Euler Problem 13: Large Sum of 1000 Digits appeared first on The Devil is in the Data.

To leave a comment for the author, please follow the link and comment on their blog: The Devil is in the Data.

R-bloggers.com offers daily e-mail updates about R news and tutorials on topics such as: Data science, Big Data, R jobs, visualization (ggplot2, Boxplots, maps, animation), programming (RStudio, Sweave, LaTeX, SQL, Eclipse, git, hadoop, Web Scraping) statistics (regression, PCA, time series, trading) and more...



If you got this far, why not subscribe for updates from the site? Choose your flavor: e-mail, twitter, RSS, or facebook...

Comments are closed.

Search R-bloggers


Sponsors

Never miss an update!
Subscribe to R-bloggers to receive
e-mails with the latest R posts.
(You will not see this message again.)

Click here to close (This popup will not appear again)