Since my first representation of the rank statistic as paired was incorrect, here is the histogram produced by the simulation

perm=sample(1:20)
saple[t]=sum(abs(sort(perm[1:10])-sort(perm[11:20])))

when . It is obviously much closer to zero than previously.

An interesting change is that the regression of the log-mean on produces

> lm(log(memean)~log(enn))
Call:
lm(formula = log(memean) ~ log(enn))
Coefficients:
(Intercept) log(enn)
-1.162 1.499

meaning that the mean is in rather than in or :

> summary(lm(memean~eth-1))
Coefficients:
Estimate Std. Error t value Pr(>|t|)
eth 0.3117990 0.0002719 1147 <2e-16 ***

with a very good fit.

Filed under: R, Statistics Tagged: Le Monde, puzzle, R, Spearman rank test

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**Tags:** Le Monde, puzzle, R, Spearman rank test, statistics